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<p>Transforming according to the table, to get</p>
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\begin{equation*}
s^2Y -s y(0) -y'(0) = \frac{10}{s}
+ 10 e^{-s}
\end{equation*}
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\begin{equation*}
{\rm so, \ rearranging} \ \ \
Y(s)=\frac{10}{s^3} + \frac{10e^{-s}}{s^2} =
5\frac{2}{s^3}+10 e^{-s}\frac{1}{s^2}
\end{equation*}
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